The position of a certain particle depends on time according to the following equation. X(t)=t^-5.2t+1.2 X is in meters and t is in seconds. A) find the displacement and average velocity for the interval 3.4s less than or equal to t less than or equal to 4.5a
X = t² - 5.2t + 1.2 At time 3.4s . . . X = (3.4)² - (5.2)(3.4) + 1.2 = -4.92m At time 4.5s . . . X = (4.5)² - (5.2)(4.5) + 1.2 = -1.95m The displacement over that interval is (-1.95m) - (-4.92m) = +2.97m Average velocity = (displacement) / (time for the displacement) in the direction of the displacement. Time interval = (4.5s - 3.4s) = 1.1 second Average velocity = 2.97m / 1.1s = 2.7 m/s in the direction of the displacement.