jennyphan22

Which two numbers have a difference of 5 and a product of 3.36???

x - y = 5 x.y = 3.36 $(x-y)^2=5^2$ $x^{2} -2xy + y^{2} =25$ $x^{2} + y^{2}=25+6.72=31,72$ $(x+y)^2= x^{2} +2xy+ y^{2} =31,72 + 6,72 = 38,44$ $\sqrt{(x+y)^2}= \sqrt{38,44}$ x+y= 6,2  and we know that x - y= 5 x+y+x-y=6,2 + 5 2x=11,2 x=5,6 so then y=0,6 Answer: x= 5,6 y= 0,6