Mathematics

# Would this be factorised fully? Or would I have to cancel the 4 and 6? But to what?

$4x^2+6xy=2x(2x+3y)$
$4x^2 - 6xy = (2 x) \cdot (2 x) - (2 x) \cdot (3y) = 2x(2x - 3y)$